3b^2-8=68

Solution for 3b^2-8=68 equation:

3b^2-8=68

We move all terms to the left:

3b^2-8-(68)=0

We add all the numbers together, and all the variables

3b^2-76=0

a = 3; b = 0; c = -76;
Δ = b2-4ac
Δ = 02-4·3·(-76)
Δ = 912
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{912}=\sqrt{16*57}=\sqrt{16}*\sqrt{57}=4\sqrt{57}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{57}}{2*3}=\frac{0-4\sqrt{57}}{6}
=-\frac{4\sqrt{57}}{6}
=-\frac{2\sqrt{57}}{3}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{57}}{2*3}=\frac{0+4\sqrt{57}}{6}
=\frac{4\sqrt{57}}{6}
=\frac{2\sqrt{57}}{3}
$